145-二叉树的后序遍历
思路:遍历
ts
function postorderTraversal(root: TreeNode | null): number[] {
const arr = []
traverse(root)
return arr
function traverse(root: TreeNode | null) {
if (root == null) return
traverse(root.left)
traverse(root.right)
arr.push(root.val)
}
}function postorderTraversal(root: TreeNode | null): number[] {
const arr = []
traverse(root)
return arr
function traverse(root: TreeNode | null) {
if (root == null) return
traverse(root.left)
traverse(root.right)
arr.push(root.val)
}
}
Ayingotts's notes