404-左叶子之和
思路:递归
ts
function sumOfLeftLeaves(root: TreeNode | null): number {
let sum = 0
traverse(root)
return sum
function traverse(node: TreeNode | null) {
if (node === null) return
const left = node.left
// node.left 是单独的节点时
if (left && !left.left && !left.right) sum += left.val
// left 仍有子节点,继续递归
traverse(left)
traverse(node.right)
}
}function sumOfLeftLeaves(root: TreeNode | null): number {
let sum = 0
traverse(root)
return sum
function traverse(node: TreeNode | null) {
if (node === null) return
const left = node.left
// node.left 是单独的节点时
if (left && !left.left && !left.right) sum += left.val
// left 仍有子节点,继续递归
traverse(left)
traverse(node.right)
}
}
Ayingotts's notes